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Question

$\mathrm{T}=\frac{2 \mathrm{u} \sin 	heta}{\sigma}=6$ seconds

$4 \sin 	heta=3 g \ldots \ldots(i)$

solve $(1)$ $\&(2)$ to get

$	an \alp

Vedclass · Accepted Answer

$20 \sqrt 3 \,m/s, 60^o$

Vedclass · Answer

$\mathrm{T}=\frac{2 \mathrm{u} \sin 	heta}{\sigma}=6$ seconds

$4 \sin 	heta=3 g \ldots \ldots(i)$

solve $(1)$ $\&(2)$ to get

$	an \alpha=\frac{4 \sin 	heta-g t}{4 \cos 	heta}$

$	an 30^{\circ}=\frac{4 \sin 	heta-g 	imes 2}{4 \cos 	heta}$

$\frac{1}{\sqrt{3}}=\frac{3 g-2 g}{4 \cos 	heta}$

$4 \cos 	heta=\sqrt{3} \mathrm{g}$         $...(2)$

Solve $(1)$ and $(2)$ to get

Two seconds after projection a projectile is travelling in a direction inclined at $30^o$ to horizontal, after one more second it is travelling horizontally. What is the magnitude and direction of its velocity at initial point

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